Question

7^(log base 7 (999)

Answer 1

by definition of logs this = 999

Answer 2

dont understand

Answer 3

The exponent and logarithm are inverses of each other.
\( 7^{\log_7 x} = \log_7 7^x = x \)

Answer 4

clear now

Answer 5

In another sense, the logarithm gives the power to raise 7 to, to get the value of x.
\( \log_7 x = y \qquad 7^y = x \)
So raising the value of the logarithm to the power of 7, gets you back where you started. Just offering another viewpoint; it isn't necessary if the first makes sense though. :)