How do you do a chemistry problem like this? what is the theoretical E cell
It has been a while since chem 2, but I think this is the answer 1.) cu+2= 0.34 constant, given 1.0M/.10M,R=gas constant 8.314,T=temp in kelvin standard 298.15, n= total electrons, F=Fardays constant 96,500, Q=1.0/.01 Formula= Ecell=Ecell -(RT/nF) ln Q 2.) So E cell= 0.34-( 8.314J*298.15/ 4*96500 J) * ln(1.0M/.01M) Ecell= 0.31
this is the Nernst equation for a cell voltage under non-standard conditions. @n648c788 has given the correct formula. You use the standard potential voltage, minus the correction factor of \(\frac{RT}{nF}*ln(Q)\). The rest is just plugging in
kay thanks guys i didn't knw what its caed and ended up with a cmpetey different number i had ended up with .351 but after ding it that way i end up with the same thing.
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