The value of 123−−−√ lies between which two consecutive integers?

Question

phi · Answer

?
can you use the equation editor, or explain the question better?

anonymous · Answer

it says

phi · Answer

I would write down some integers and their squares.
until I find the pair that works.
for example, I know 10 squared is 10*10 = 100  which is smaller than 123
if 11*11 is bigger than 123 then we found the answer.  otherwise we keep going...

myininaya · Answer

is 11*11=121 or do i actually need to multiply that

phi · Answer

I assume "modern" students can't do 11*11 in their head (but I could be wrong)

myininaya · Answer

oh oops you said if 
sorry

anonymous · Answer

log
16
256=? what about this one?

phi · Answer

You should know 
$$ \sqrt{100} = \sqrt{10 \cdot 10} = 10 $$
right ?
so it makes sense that 
$\sqrt{123} $ is bigger than 10
but we should test 11 and 12 also

phi · Answer

Did you answer the sqrt(123) question ?

anonymous · Answer

yup

anonymous · Answer

11 and 12. i am on a knew question now

phi · Answer

ok.  But please make it a new post.

anonymous · Answer

i posted on here already

anonymous · Answer

log
16
256=?

mathstudent55 · Answer

You mean
$\large \log_{16} 256$
If so, you are looking for the exponent you need to raise 16 to, to get 256.
Hint: Write 256 as a power of 16.