Question

calc help!

Answer 1

\[y=(f(x))^{g(x)} , f(x)>0 \\ y=(f(x))^{g(x)} \\ \ln(y)=\ln([(f(x))^{g(x)}] \\ \ln(y)=g(x) \cdot \ln(f(x)) \\ \frac{y'}{y}=g'(x) \ln(f(x))+g(x) \cdot \frac{f'(x)}{f(x)}\]
Then you can find y' by multiplying y on both sides

Answer 2

So comparing your answer to my answer do you think you are done?

Answer 3

I wonder if you multiplied y on both side yet?

Answer 4

or if you differentiated ln(y) correclty.

Answer 5

oh i was wrong

Answer 6

not totally

Answer 7

I'm just saying it looks like you are one step away from done

Answer 8

unless you differentiated the ln(y) incorrectly

Answer 9

when you differentiate ln(y) what did you get?

Answer 10

im redoing it with your steps, one sec(:

Answer 11

@myininaya

Answer 12

Ok ln(y)=3xln(x+8)

Answer 13

you agree ?

Answer 14

with you have ln(y)=3xln(x+8) yes

Answer 15

then differentiate both sides

Answer 16

@iambatman do you agree?

Answer 17

well you differentiate both sides

Answer 18

not just one side

Answer 19

you have ln(y)=3xln(x+8)

Answer 20

so take derivative of both sides w.r.t x

Answer 21

ohhh

Answer 22

\[\frac{d}{dx}(\ln(y))=\frac{d}{dx}(3x \ln(x+8))\]

Answer 23

beautiful

Answer 24

:)