y+1=2/3(x+3) write in standard form. I don't know what to do with the +3 at the end.

Question

y+1=2/3(x+3) write in standard form.  I don't know what to do with the +3 at the end.

anonymous · Answer

What is the question

anonymous · Answer

I have to write y+1=2/3(x+3) in standard form.

anonymous · Answer

y+2= -3(x-1)
y+2= -3x+3
3x+y-1=0

so your final answer is: 3x+y-1

anonymous · Answer

Do you understand?

amistre64 · Answer

almost a good example, just a few things off in it

anonymous · Answer

I don't think thats what teacher is looking for.   Something like... -2x+3y=???  I don't know what to do with the +1 or the +3

amistre64 · Answer

in your example:  3x+y-1=0 is good, or 3x+y=1 is fine

amistre64 · Answer

standard form is Ax + By = C  such that A is not negative.

amistre64 · Answer

y+1=2/3(x+3)

3y+3=2(x+3)

3y+3=2x+6

-2x+3y=3

multiply thru by -1 so that we dont have a -2 starting out

amistre64 · Answer

once we got here:

3y+3=2x+6

we could have just moved the y stuff over and the constants to the other side, since we have a positive x coefficient

3=2x-3y+6

-3=2x-3y