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Geometry 13 Online
OpenStudy (anonymous):

math distance

OpenStudy (anonymous):

OpenStudy (anonymous):

@studygirl

OpenStudy (lyrae):

The distance formula \[distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\] Maby you recognize it as the Pythagorean theorem:|dw:1414371907671:dw|

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

0,1 and 4,4 so

OpenStudy (anonymous):

i got 8.06

OpenStudy (anonymous):

is that right, if not i can tell u tell u how i got my answer

OpenStudy (anonymous):

i squared 1 and then added 4plus 4 got 8 squared that and got 64, added the one got 65, then i found the square root of that

OpenStudy (lyrae):

Nah, not quite. Maby it's easier like this (0, 1) (4, 4) x1 y1 x2 y2

OpenStudy (lyrae):

And then you insert the values into the formula.

OpenStudy (anonymous):

thanks ok now it makes sense

OpenStudy (anonymous):

i'll tell u what i come up with in a minute

OpenStudy (anonymous):

i came up with 5 =D

OpenStudy (lyrae):

Yeah, me to :)

OpenStudy (anonymous):

Thanks You're a good tutor!

OpenStudy (lyrae):

Haha thx :)

OpenStudy (anonymous):

yw! I have another question i'll post it in another question so i can medal u it's about finding midpoints

OpenStudy (anonymous):

do u know how to do that

OpenStudy (anonymous):

same concept with the line but midpoint

OpenStudy (lyrae):

Yeah I know, there's a formula for that to! Tag me and I'll be there!

OpenStudy (anonymous):

ok thx i will

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