Geometry
13 Online
OpenStudy (anonymous):
math distance
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OpenStudy (anonymous):
OpenStudy (anonymous):
@studygirl
OpenStudy (lyrae):
The distance formula
\[distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\]
Maby you recognize it as the Pythagorean theorem:|dw:1414371907671:dw|
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
0,1 and 4,4 so
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OpenStudy (anonymous):
i got 8.06
OpenStudy (anonymous):
is that right, if not i can tell u tell u how i got my answer
OpenStudy (anonymous):
i squared 1 and then added 4plus 4 got 8 squared that and got 64, added the one got 65, then i found the square root of that
OpenStudy (lyrae):
Nah, not quite.
Maby it's easier like this
(0, 1) (4, 4)
x1 y1 x2 y2
OpenStudy (lyrae):
And then you insert the values into the formula.
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OpenStudy (anonymous):
thanks ok now it makes sense
OpenStudy (anonymous):
i'll tell u what i come up with in a minute
OpenStudy (anonymous):
i came up with 5 =D
OpenStudy (lyrae):
Yeah, me to :)
OpenStudy (anonymous):
Thanks You're a good tutor!
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OpenStudy (lyrae):
Haha thx :)
OpenStudy (anonymous):
yw! I have another question i'll post it in another question so i can medal u it's about finding midpoints
OpenStudy (anonymous):
do u know how to do that
OpenStudy (anonymous):
same concept with the line but midpoint
OpenStudy (lyrae):
Yeah I know, there's a formula for that to! Tag me and I'll be there!
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OpenStudy (anonymous):
ok thx i will