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Mathematics 21 Online
Nnesha (nnesha):

need help if you can

Nnesha (nnesha):

\[0x ^{7} + 2x ^{6} + 0x ^{5} - x ^{4} - x ^{3} - 9x ^{2} - 9x - 7\]

Nnesha (nnesha):

"intervals on which it is increasing" ( -.885 , -.509) , ( 1.106 , infinity) ( i find this i don't know right or not ) and "intervals which it is decreasing" ( infinity , -.885),( -.509 , 1.106) ( same with this one ) is this right or not

OpenStudy (amistre64):

finding critical points with a derivative might be an idea

OpenStudy (amistre64):

\[2x ^{6} - x ^{4} - x ^{3} - 9x ^{2} - 9x - 7:it~resembles~x^2~in~'shape'\] \[12x ^{5} - 4x ^{3} - 3x ^{2} - 18x - 9=0\]

OpenStudy (amistre64):

where the 0 coefficients on purpose?

Nnesha (nnesha):

oh wait how you get 12x^5

OpenStudy (amistre64):

derivative of what you gave us

Nnesha (nnesha):

0 is because to keep the x degree on line this polynomial are not given by teacher or from books we have to make that

OpenStudy (amistre64):

oh, then its not a proper polynomial, since the coefficient of the first term is not to be 0

OpenStudy (amistre64):

coeff of the highest degree tha tis

Nnesha (nnesha):

well 0's are just for x degree it can be \[2x ^{6} - x ^{4} - x ^{3} -9x ^{2} - 9x -7\]

Nnesha (nnesha):

this is my actual polynomial

OpenStudy (amistre64):

yes :) thats better, and its derivative is? this is calculus right?

Nnesha (nnesha):

no its not calculus

Nnesha (nnesha):

its just simple math 3

OpenStudy (amistre64):

thats not a name im familiar with

Nnesha (nnesha):

what math 3 ???

OpenStudy (amistre64):

yeah

OpenStudy (xapproachesinfinity):

Most likely precalc?

OpenStudy (amistre64):

how do you go about finding the intervals?

Nnesha (nnesha):

graph the polynomial and then find increasing and decreasing left to right x values

OpenStudy (amistre64):

graphing ... im used to trying to do things by hand, or by brain :) old school i spose

Nnesha (nnesha):

yeah i like that too but my teacher said to use calculator

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=y%3D2x6%2B%E2%88%92x4%E2%88%92x3%E2%88%929x2%E2%88%929x%E2%88%927 your function is a bit complicated in that its hard to see visually where some of the finer intervals are

OpenStudy (xapproachesinfinity):

eh you can't graph those big degree by hand unless you use differentiation

Nnesha (nnesha):

i used desmos and my teacher allowed to use that

OpenStudy (xapproachesinfinity):

you can graph easy ones by hand! using few tips that student study in precalc

OpenStudy (amistre64):

http://www.wolframalpha.com/input/?i=12x5%E2%88%924x3%E2%88%923x2%E2%88%9218x%E2%88%929%3D0 graphing the derivative of it gives a better indication where the slope of the curve is increasing (+ values) and decreasing (- values)

OpenStudy (xapproachesinfinity):

but when it comes to crazy polynomials it is an impossible job to do things by hand lol

OpenStudy (xapproachesinfinity):

without calculus that is

OpenStudy (amistre64):

|dw:1414373583309:dw|

OpenStudy (amistre64):

use your own approximations :)

Nnesha (nnesha):

i don't know how you get 12x^5 -4x^3 - 3x^2 - 18x -9

OpenStudy (amistre64):

it doesnt matter, if your graphing your function, then do that. i took a derivative and set it to 0 to find the apprixmation of the intervals. you should be able to compare that to your own sighted method

OpenStudy (amistre64):

|dw:1414373990539:dw| "intervals on which it is increasing" ( -.885 , -.509) , ( 1.106 , infinity) "intervals which it is decreasing" ( infinity , -.885),( -.509 , 1.106) ( same with this one )

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