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Geometry 19 Online
OpenStudy (anonymous):

here it is

OpenStudy (confluxepic):

What?

OpenStudy (anonymous):

OpenStudy (confluxepic):

First find the distance.

OpenStudy (confluxepic):

\[d =\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]

OpenStudy (anonymous):

ok i'll work it out un segundo

OpenStudy (anonymous):

i got 5

OpenStudy (lyrae):

It's half the distance of the two points|dw:1414373818847:dw| So it will simply be \[midpoint = (\frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2 })\]

OpenStudy (anonymous):

ok it's either 2 2/5, 2 5/2, 5 2/2, or 2 5/5

OpenStudy (lyrae):

Yeah, so what do you get if you insert the cordinates like in the previous question?

OpenStudy (anonymous):

i don't know im confused with the mixed numbers

OpenStudy (lyrae):

a little reminder (0, 1) (4, 4) x1 y1 x2 y2

OpenStudy (confluxepic):

Substitute the the values into the midpoint formula.

OpenStudy (anonymous):

i got 2 5/2

OpenStudy (lyrae):

\[midpoint = (\frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2 })\]Is the coordinates for the actual midpoint. So if I for example have the points (1, 3) and (2, 5) the midpoint is going to be \[midpoint = (\frac{ 1 + 2 }{ 2 }, \frac{ 3 + 5 }{ 2 }) = (\frac{ 3}{ 2 }, 4)\]

OpenStudy (lyrae):

That's correct!

OpenStudy (anonymous):

omgoshh took me long enough.. thank you!

OpenStudy (confluxepic):

You're welcome. Thanks @Lyrae for doing most of the work.

OpenStudy (lyrae):

Hehe no worries! Yw :)

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