here it is
What?
First find the distance.
\[d =\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]
ok i'll work it out un segundo
i got 5
It's half the distance of the two points|dw:1414373818847:dw| So it will simply be \[midpoint = (\frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2 })\]
ok it's either 2 2/5, 2 5/2, 5 2/2, or 2 5/5
Yeah, so what do you get if you insert the cordinates like in the previous question?
i don't know im confused with the mixed numbers
a little reminder (0, 1) (4, 4) x1 y1 x2 y2
Substitute the the values into the midpoint formula.
i got 2 5/2
\[midpoint = (\frac{ x_1 + x_2 }{ 2 }, \frac{ y_1 + y_2 }{ 2 })\]Is the coordinates for the actual midpoint. So if I for example have the points (1, 3) and (2, 5) the midpoint is going to be \[midpoint = (\frac{ 1 + 2 }{ 2 }, \frac{ 3 + 5 }{ 2 }) = (\frac{ 3}{ 2 }, 4)\]
That's correct!
omgoshh took me long enough.. thank you!
You're welcome. Thanks @Lyrae for doing most of the work.
Hehe no worries! Yw :)
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