Question

sin^-1((sqrt3)/2)

Answer 1

The question is basically asking you at what angle \(\theta\) does \(sin\theta\) = \(\frac{\sqrt{3}}{2}\). Now, there are two values where this is true, but you can only pick one of them. All values for sin^(-1)x must be in the interval [-pi/2, pi/2]. So whether you know off the top of your head by now or you need to look at a unit circle, simply find where in the interval of [-pi/2, pi/2] sin has a value of \(\frac{\sqrt{3}}{2}\)