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OpenStudy (anonymous):

How many grams of NH3 can be produced from 2.93mol of N2 and excess H2?

OpenStudy (anonymous):

1 mol of N2 is 28 gms, thus, 2.93mol is 84 gms. According to the equation- \[N _{2} + 3H _{2}\rightarrow 2NH _{3}\] 28gms (1mol) of N2 produces 34gms of NH3 so, 84gms of N2 will produce: 28gms of N2----->34gms of NH3 84gms of N2----->\[28\div84=34\div x\] \[x= (34*84)\div28\] Answer: 102gms

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