Question

@shinalcantara @satellite73 This is my last on it would be amazing if you can help me

Answer 1

yeah?

Answer 2

One sec

Answer 3

@shinalcantara

Answer 4

Please Help Its man last question <3

Answer 5

*my

Answer 6

@shinalcantara

Answer 7

Seriously though can you please help me @shinalcantara This is my last question, i won't have to bother you again :)

Answer 8

@Secret-Ninja @satellite73

Answer 9

for the first part, all you have to do is multiply
\[3.9(10^{33}) \times 3.25(10^3)\]
expressing 3.25 x 10^3 in standard form you'll have:
(disregard first 10^33. we'll deal with it later after multiplying)
\[3.9 \times 3,250 = 12,675\]
since 3.9 is multiplied to 10^(33) then it would follow that 12,675 will be multiplied with the same quantity. so it would be:
\[12,675(10^{33}) \rightarrow 1.2675(10^{37})\]

Answer 10

Sorry, I don't know this. :/

Answer 11

for part B:
1.435x10^(-3) mm in standard form is 0.001435 mm.. it's way way toooooo small i don't know if it can still be measured by a caliper (-_-)!
1.435x10^(3) mm is just 1.435m. so it would be more reasonable with that distance

Answer 12

@shinalcantara Can you help me with the second part, thats all i need.

Answer 13

what is it?

Answer 14

@shinalcantara Hello ?

Answer 15

yeah?

Answer 16

@satellite73 @tkhunny @shinalcantara I need help with part B Please :)

Answer 17

i've posted it above.. read up up up scroll scroll scroll xD

Answer 18

Negative exponent with mm is very, very tiny. Not a good railroad track.