Graph 30x/x^2+2

Question

Graph 30x/x^2+2

anonymous · Answer

How come this graph passes through y=0?

anonymous · Answer

shouldnt there be a hole at y=0?

anonymous · Answer

You probably want to put some parentheses in the expression or use the equation editor.

anonymous · Answer

$$y=\frac{ 30x }{ x^2+2 }$$

anonymous · Answer

@ganeshie8

campbell_st · Answer

well if you looks at the equation, the y- intercept is y = 0

substitute x = 0

y = (30*0)/(0^2 + 2) 

so the point (0,0) is the y- intercept.

anonymous · Answer

but there is a horizontal asymptote at y=0

campbell_st · Answer

there is no hole in the curve the denominator is 

$$x^2 + 2$$

so there are no restrictions, the denominator will always return a real number

campbell_st · Answer

yes that's correct.... y = 0 is the horizontal asymptote... so as x gets large the curve approaches zero..

anonymous · Answer

oh okay, this means i got this question wrong it was on my test, and i said there will be a hole at (0,0) :c

anonymous · Answer

I had the right answer and then i changed it to that sadly

campbell_st · Answer

well if you think about it...if x is negative, squaring it returns a positive.... 

so you will always have a denominator that is a positive value...

anonymous · Answer

yea, oh well true, but eh oh well life goes on, this is the only question that confused me. Thanks for the clarification.

campbell_st · Answer

glad to help