Mathematics
6 Online
OpenStudy (anonymous):
The roots of y in the equation y2−2y=-9/2 are ?
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OpenStudy (anonymous):
are you familiar with the quadratic equation, or completing the square?
OpenStudy (anonymous):
no i am not fimiliar
OpenStudy (anonymous):
Complete the square or use quadratic formula.
OpenStudy (anonymous):
i dont know what complete the square is.
OpenStudy (anonymous):
Are you learning about imaginary numbers?
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OpenStudy (anonymous):
somewhat yes.
OpenStudy (anonymous):
ok is that a y2 or a \[y^{2}\]
OpenStudy (anonymous):
y^2
OpenStudy (anonymous):
ok lets use the Quadratic formula
OpenStudy (anonymous):
a=1
b=2
c=-9/2
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OpenStudy (anonymous):
\[\frac{ -b \pm \sqrt{b ^{2}-4(a)(c)} }{2 (a) }\]
OpenStudy (anonymous):
shouldnt b=-2?
OpenStudy (anonymous):
yes sorry i messed up
OpenStudy (anonymous):
a=1
b=-2
c=-9/2
OpenStudy (anonymous):
\[\frac{ 2\pm \sqrt{2^{2}-4(1)(\frac{ -9 }{ 2 })} }{ 2(1) }\]
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OpenStudy (anonymous):
okay this is where i start to get confused
OpenStudy (anonymous):
ok lets work throughout it by sections
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
lets start here
\[\sqrt{2^{2}-4(1)(-\frac{ 9 }{ 2 })}\]
OpenStudy (anonymous):
\[\sqrt{4+18}\]
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OpenStudy (anonymous):
\[\sqrt{22}\]
OpenStudy (anonymous):
\[\sqrt{22}\]
OpenStudy (anonymous):
\[\frac{ 2 \pm \sqrt{22} }{ 2 }\]
OpenStudy (anonymous):
okay im not sure what this equals
OpenStudy (anonymous):
I'm sorry i messed up again the -9/2 should have turned positive so it would have been \[\sqrt{4-18}\]
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OpenStudy (anonymous):
\[\sqrt{-14}\]
OpenStudy (anonymous):
\[\frac{ 2\pm \sqrt{-14} }{ 2 }\]
OpenStudy (anonymous):
\[\frac{ 2\pm \iota \sqrt{14} }{ 2 }\]
OpenStudy (anonymous):
that is as low as it will go
OpenStudy (anonymous):
okay thanks so much!!!
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OpenStudy (anonymous):
no problem!