The attachment is a graph of F'(x) (a) Find the critical values for F(x). (b) Give the intervals where F(x) is increasing. (c) Give the intervals where F(x) is decreasing. (d) Find the x-coordinates of the relative extrema for F(x). relative max: relative min:
Function has 3 critical values it appears.
Remember critical numbers happen when f'=0 when do you have horizontal tangents?
7,15
and 0
2/3
2/3 means you got 2 out of 3 correct
do you have a horizontal tangent at x=15?
The graph is a function of F'(x), don't derivatives pass through F(x) horizontal tangents?
oh the attachment is f'
not f
then you are right
yay!, I find it harder to answer parts b,c, and d
f is increasing when f'>0 f is decreasing when f'<0
so when is f'>0 (when is the graph above the x-axis)
interval (7,15)
right so since f'>0 on (7,15) then f is increasing on (7,15)
oh ok. so decreasing (- inifnity,7) U (15, inifnity)?
because the function is below the x-axis?
well i might say (-inf, 0) U (0,7) U (15,inf)
just because at x=0 the graph is resting
right! thank you.
so how would we be able to find the relative max/min?
Well now you know where the function is increasing and decreasing. When the function switches from increasing to decreasing at x=a we have a max at x=a. If we have the function switches from decreasing to increasing at x=a we would have a min at x=a.
for example |dw:1414450206864:dw|
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