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Mathematics 11 Online
OpenStudy (anonymous):

The attachment is a graph of F'(x) (a) Find the critical values for F(x). (b) Give the intervals where F(x) is increasing. (c) Give the intervals where F(x) is decreasing. (d) Find the x-coordinates of the relative extrema for F(x). relative max: relative min:

OpenStudy (anonymous):

myininaya (myininaya):

Function has 3 critical values it appears.

myininaya (myininaya):

Remember critical numbers happen when f'=0 when do you have horizontal tangents?

OpenStudy (anonymous):

7,15

OpenStudy (anonymous):

and 0

myininaya (myininaya):

2/3

myininaya (myininaya):

2/3 means you got 2 out of 3 correct

myininaya (myininaya):

do you have a horizontal tangent at x=15?

OpenStudy (anonymous):

The graph is a function of F'(x), don't derivatives pass through F(x) horizontal tangents?

myininaya (myininaya):

oh the attachment is f'

myininaya (myininaya):

not f

myininaya (myininaya):

then you are right

OpenStudy (anonymous):

yay!, I find it harder to answer parts b,c, and d

myininaya (myininaya):

f is increasing when f'>0 f is decreasing when f'<0

myininaya (myininaya):

so when is f'>0 (when is the graph above the x-axis)

OpenStudy (anonymous):

interval (7,15)

myininaya (myininaya):

right so since f'>0 on (7,15) then f is increasing on (7,15)

OpenStudy (anonymous):

oh ok. so decreasing (- inifnity,7) U (15, inifnity)?

OpenStudy (anonymous):

because the function is below the x-axis?

myininaya (myininaya):

well i might say (-inf, 0) U (0,7) U (15,inf)

myininaya (myininaya):

just because at x=0 the graph is resting

OpenStudy (anonymous):

right! thank you.

OpenStudy (anonymous):

so how would we be able to find the relative max/min?

myininaya (myininaya):

Well now you know where the function is increasing and decreasing. When the function switches from increasing to decreasing at x=a we have a max at x=a. If we have the function switches from decreasing to increasing at x=a we would have a min at x=a.

myininaya (myininaya):

for example |dw:1414450206864:dw|

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