The cost of controlling emissions at a firm rises rapidly as the amount of emissions reduced increases. Here is a possible model:
C(q) = 4,900 + 96q2
where q is the reduction in emissions (in pounds of pollutant per day) and C is the daily cost to the firm (in dollars) of this reduction. What level of reduction corresponds to the lowest average cost per pound of pollutant? (Round your answer to two decimal places.)
pounds of pollutant per day
What would be the resulting average cost to the nearest dollar?
$ per pound
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (xapproachesinfinity):
the lowest would be you minimum the way you know it
when you studied parabolas
OpenStudy (xapproachesinfinity):
Do you know how to find the minimum or maximum?
well in this case it is a minimum since 96 is positive
OpenStudy (anonymous):
yea i think so! dont i just find the derivative and then set it equal to 0 and then plug back in?
OpenStudy (xapproachesinfinity):
eh you learned about derivatives
okay you need to find critical points
find the min and plug it in
you a pretty good idea here^_^
OpenStudy (xapproachesinfinity):
I thought the question was given to you in precalc
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no its business calc
OpenStudy (xapproachesinfinity):
it is the same thing! just you lecture focuses on business models
OpenStudy (anonymous):
so i find the derivative then = 0 right?
OpenStudy (xapproachesinfinity):
yep! now go for it
OpenStudy (anonymous):
i got 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
192q for the deriv and then =0 and i got 0??
OpenStudy (xapproachesinfinity):
yes you should get f'(0)=0
OpenStudy (xapproachesinfinity):
c'(q) i mean
OpenStudy (anonymous):
so thats my answer?
OpenStudy (xapproachesinfinity):
no!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or what do i have to do next?
OpenStudy (xapproachesinfinity):
that's just a critical point! you need to find if it is min or not
OpenStudy (xapproachesinfinity):
you need to check if the derivative changes the sign left of 0 and right of 0
if not that wouldn't be a min
OpenStudy (xapproachesinfinity):
well obviously left of zero the derivative is always negative
and right of zero it is positive so
f(0) is a minimum
OpenStudy (anonymous):
its a min
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
right!
OpenStudy (xapproachesinfinity):
f(0) not 0
OpenStudy (xapproachesinfinity):
yes we have a min
OpenStudy (anonymous):
so whats next?
OpenStudy (xapproachesinfinity):
f(0) find the value?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
isnt it just 4900?
OpenStudy (xapproachesinfinity):
yes!
OpenStudy (anonymous):
okay...
OpenStudy (xapproachesinfinity):
the level of reduction is 0
the lowest average that corresponds to that is 4900
OpenStudy (xapproachesinfinity):
you are in good shape to go
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
it says its wrong?
OpenStudy (xapproachesinfinity):
eh! let met reread the problem
OpenStudy (anonymous):
mmkay
OpenStudy (anonymous):
anything?
OpenStudy (xapproachesinfinity):
I'm graphing it!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay its okay! i actually have to leave to work in a few minutes so ill try and figure it out later:/