Write an equation in slope-intercept form for the the line that is parallel to 3x+2y=12 and contains the point (6,-2).
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Since the lines have to be parallel the slopes also have to be the same.
The slope-intercept form is an equation in this form:\(\ y = mx + b\), where\(\ m\) is the slope and\(\ b\) is the location where the line touches the y-axis when\(\ x=0\). In a line that is parallel to\(\ y = mx + b\) the only thing that changes is\(\ b\). It means that the slope\(\ m\) is the same but it touches the y-axis in a different place when\(\ x=0\).
I know, I got the answer an y=-3/2x+6 but instead of 6 it should be 7 but I want to know how
The equation that was given cannot me further manipulated. You must end up with 2 equation: that that was given (written now in slope-intercept form) and the new one that you found.
True.
So I cannot go farther than the equation?
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