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Mathematics 5 Online
OpenStudy (anonymous):

could you guys help me with with a hint for this proof on limits ?

OpenStudy (anonymous):

OpenStudy (anonymous):

Im sorry i have looked at it so mant times but dont understand it

OpenStudy (dumbcow):

well L'Hopitals would make this real easy :{

OpenStudy (anonymous):

hehehe but what would be the albegra proof

OpenStudy (dumbcow):

it prob has something to do with this http://en.wikipedia.org/wiki/Differentiation_of_trigonometric_functions#Derivative_of_the_sine_function

OpenStudy (anonymous):

nice i ll take a look

OpenStudy (anonymous):

hmm yeah that has something to do with derivatives

OpenStudy (jdoe0001):

hmmm

OpenStudy (jdoe0001):

you've covered how to use "u" to group a set, righgt?

OpenStudy (anonymous):

hmmm no really

OpenStudy (dumbcow):

rewrite limit as this \[\lim_{h \rightarrow 0} \frac{\sin(a+h) - \sin a}{h}\] where h = x-a \[\lim_{h \rightarrow 0} \frac{\sin a \cos h + \cos a \sin h - \sin a}{h}\] \[\lim_{h \rightarrow 0} \frac{\sin h}{h} \cos a + (\frac{\cos h -1}{h}) \sin a\]

OpenStudy (anonymous):

ohhh i see

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