How do i graph a circle when i have the center of 4,3 and radius=6. What are the intercepts

Question

anonymous · Answer

$$(x - h)^{2} +(y-k)^{2} = r ^{2}$$

this is the general equation of a circle centered at (h, k) and radius r.  does this information help?

anonymous · Answer

to graph, you could either just plot points of that equation -- or start at the center (4, 3), and then go 6 units in any direction and draw a circle.

anonymous · Answer

not really i have the circle graphed but i dont know how to find all the four intersections

anonymous · Answer

like x and y intercepts?  to find x-intercepts, let y = 0 and solve for x.  for y-intercepts, let x = 0 and solve for y.  how many solutions you get depend on how many times the circle intersects the axes

anonymous · Answer

what is it i dont really know how to put it in a calculator

anonymous · Answer

what kind of calculator do you use

anonymous · Answer

ti 84

anonymous · Answer

ok do you agree that the equation of this circle is

$$(x - 4)^{2} + (y - 3)^{2} = 36$$

?

anonymous · Answer

i think so because i started off with x^2+y^2-8x-6y-11=0

anonymous · Answer

that is correct.

to enter it into your calculator you will have to solve for y.

$$(y - 3)^{2} = 36 - (x - 4)^{2}$$
$$y = 3 \pm \sqrt{36 - (x - 4)^{2}}$$

so you will have to enter two equations into your calculator

anonymous · Answer

and what do i enter?

anonymous · Answer

y = 3 + sqrt(36 -(x - 4)^2) and y = 3 - sqrt(36 - (x - 4)^2)

anonymous · Answer

each equation will graph 1/2 of the circle.  both of them will generate a complete circle.  the reason only half can be generated at a time is because a circle is not a function (it fails the vertical line test) but when you cut the circle in half horizontally, you get two functions that, combined, generate the whole circle

anonymous · Answer

Hmm what is the 4 intersects