Question

I NEED HELP SO BAD I WILL MEDAL FAN AND WRITE TESTIMONIAL!!!!! QUESTION IN COMMENTS

Answer 1

A ball is thrown into the air with an upward velocity of 32 feet per second. Its height, h, in feet after t
seconds is given by the function h(t) = –16t² + 32t + 6. What is the ball’s maximum height? How long does it
take the ball to reach its maximum height? Round to the nearest hundredth, if necessary. (1 point)
Reaches a maximum height of 22 feet after 1.00 second.
Reaches a maximum height of 22 feet after 2.00 seconds.
Reaches a maximum height of 44 feet after 2.17 seconds.
Reaches a maximum height of 11 feet after 2.17 seconds.

Answer 2

The maximum height of the ball, is when velocity is 0

have you done calculus? differentiation or no?

Answer 3

This is algebra 1b so no calc

Answer 4

ok.

well not sure how to get you to a function for velocity. Other than to just tell you that

velocity = -16t + 32

at the heighest point velocity is 0 (as the ball turns around to come back home)

so 0 = -16t + 32

solve that for t

t = 32/16
t = 2

Answer 5

then whack that value of time in for t in your other equation

Answer 6

one sec

Answer 7

but you can kind of see why velocity would be that.

velocity = distance/ time

= h(t)/t

and we just ignore the 6/t you get at the end, because the 6 is the initial height and that is irrespective of velocity

Answer 8

-2?