Question

Basic physics problem... please look

Answer 1

@gerryliyana

Answer 2

Physics makes me want to cry

I'm just a high school student trying to get good grades :(

Answer 3

You've been typing for a long time...

Answer 4

information is known:
Car velocity, Vc = 80 km/h (constant) = 22.2222 m/s
after 2 seconds the trooper accelerates from rest at a constant rate with a = 5 m/s2

information is asked:
the time for the trooper to catch up to the car?

Answer:
Sc = St
v t = vo t + 1.2 a t^2

Remember: the troper was late 2 seconds and starting to move from zero velocity, then
Sc = St
v t = vo t + a t
v t = (0) (t - 2) + 1.2 a (t - 2)^2

Remember: the car was travelling with constant velocity 22.2222 m/s, then
Sc = St
v t = vo t + a t
v t = (0) (t - 2) + 2/3 a (t - 2)^2
(22.2222) t = 1/2 a (t-2)^2

Remember, the acceleration of the trooper was 5 m/s2
Sc = St
v t = vo t + 1/2 a t^2
v t = (0) (t - 2) + 1/2 a (t - 2)^2
(22.2222) t =1/2. (5) (t-2)^2
(22.2222) t =2.5 (t^2 -4t + 4)
22.22t = 2.5 t^2 - 10t + 10
22.22t + 10t = 2.5t^2 + 10
32.22t = 2.5t^2 + 10
2.5t^2 + 10 - 32.22t^2 = 0

find t

Answer 5

Do I use the quadratic formula?

Answer 6

and wow thank you so much for taking the time out to explain everything you're a really kind person...

Answer 7

hold on.., i think i was wrong, let me check again

Answer 8

are you still here @micheletheresam ?

Answer 9

Yes

Answer 10

yes, i think you should use the quadratic formula to find time, t from
2.5t^2 - 32.22t + 10 = 0

Answer 11

12.57 seconds

Answer 12

For Car
S = v t = 22.222 * 12.57 = 279.33054

For the trooper
S= 1/2 a (t-2)^2 = 1/2 . 5 . (12.57 - 2)^2 = 279.31225

Answer 13

good job @micheletheresam !

Answer 14

i absolutely agree with you, the answer is 12.57 seconds
So, the trooper catch up the car after 12.57 seconds

Answer 15

Would you please help me with one more? It's my last.

Answer 16

go ahead

Answer 17

I'll make it a new question so you can get another "best response" thing