Question

How will we work with binomials containing radicals and complex numbers?

Answer 1

sounds like a philosophy question
you got an actual example?

Answer 2

(4+3i)(4-3i)
16+9
25

Answer 3

ok that looks good

Answer 4

\((a+bi)(a-bi)=x^2+b^2\) always

Answer 5

OOPS i means \(a^2+b^2\)

Answer 6

What the super smart guy is sayin O.O

Answer 7

if you multiply out
\[(a+bi)(a-bi)\] you get
\[a^2-abi+abi-bi^2\] the middle terms add up to zero, and since \(i^2=-1\) the last term is \(+b^2\) giving a final answer of
\[a^2+b^2\]