Question

Help me please! Question on the link: http://grab.by/BDHE

Answer 1

think the usual gimmick is to multiply by top and bottom by the conjugate

Answer 2

hehehe assignments online awesome :D

Answer 3

yeah, easy to cheat!

Answer 4

we can do it by hand however, if you like

Answer 5

The graph is ugly

Answer 6

it is going to be a pain to write

Answer 7

Except I don't know what I'm doing!

Answer 8

hehehe didn't thought it that way

Answer 9

2.4749

Answer 10

I fail the tests so easily and it's AP Calculus

Answer 11

Have to round the last number

Answer 12

Honestly, I thought calculus was hard at first to, but it all comes down to the basics, just review them it's not too bad then.

Answer 13

Okay that was right and what is the exact value of the limit?

Answer 14

That means you have to put it in squareroot and st00f

Answer 15

\[\sqrt{2x^2+9x+2}-\sqrt{2x^2+2x+1}\times \frac{\sqrt{2x^2+9x+2}+\sqrt{2x^2+2x+1}}{\sqrt{2x^2+9x+2}+\sqrt{2x^2+2x+1}}\]

Answer 16

finally!

Answer 17

\[\frac{ 7 }{ 2\sqrt{2} }\] i guess? Sat can check it xD

Answer 18

YES ITS RIGHT! Thank you all so much

Answer 19

probably
numerator is
\[7x-1\]denominator is \(\sqrt{2x^2}+\sqrt{2x^2}\)

Answer 20

@iambatman good eyeballs!

Answer 21

Haha there we go :P