A cyclist is acceleratingat 5m/s in 30 seconds. The cyclist initial speed is .50m/s. What will be the cyclist final speed?

Question

anonymous · Answer

v(final) = v(initial) + at
v(final)= .50 m/s + (5)(30) =

anonymous · Answer

Thats easy, the final speed is 200 m/s

Fs=Is+at
Fs=50 m/s + 5m/s^2 (30 s)
Fs=200 m/s

mrnood · Answer

that is not correct if the question is correctly written.

It says the change in speed is 5m/s (and it takes 30 s to achieve that)

so the final speed is 5.5 m/s

(IF it was meant to be 5 m/s^2 for 30 s then the above answers are correct - but it would have to be a rocket powered bike to maintain that acceleration )

@Yocy - you have misread it anyhow - the initial speed is 0.5 m/s (not 50 m/s)

mrnood · Answer

BTW - if he DID accelerate at 5 m/s^2 for 30 s then he would be doing 150.5 m/s after 30s - which is 336mph

So I think the question IS set correctly and the  total change in speed is 5m/s

anonymous · Answer

Oh yeah you're right MrNood ^^ I didn't see the period before the 50. Sorry