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Calculus conceptual question
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If y(x) is a solution to dy/dx = 2y(5=y) with y(0) = 3, then as x approaches infinity, a. y(x) increases to infinity b. y(x) increases to 5 c. y(x) decreaes to 5 d. y(x) decreases to 2 e y(x) decreases to 0 I think it's a because the derivative only depends on y and it's 5y which is always positive. Is that right?
dy/dx = 2y(5-y) *
separate the variables and integrate , find the constant of integration with the initial value
And that constant is what the function increases/decreases to?
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basically dy/dx = f(y)
so its not dependant on x
its invariant wrt to x
you would need partial fractions if you solve by seperation of variables
|dw:1414474287797:dw|
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