Question

One diagonal of a cyclic quadrilateral coincides with a diameter of a circle whose area is 36 pi cm^2. If the other diagonal which measures 8 cm meets the first diagonal at the right angles,find the area of the quadrilateral. Please help me :(

Answer 1

what's next how can i find its area? :( please help me

Answer 2

master @perl what's next? :)

Answer 3

@perl

Answer 4

you to MIT ?

Answer 5

mapua :)

Answer 6

whats mapua?

Answer 7

i mean can you guve me the solution for the problem @@perl ? :( =))

Answer 8

sure, one sec

Answer 9

If a quadrilateral has perpendicular diagonals, d1 and d2, then area=(d1 x d2)/2

Answer 10

thank youu in advance!!! you are an angel! haha =)))

Answer 11

Pi * r^2 = 36*Pi
r^2 = 36
r = 6
now
diameter = 2*r
so
diameter = 2*6 = 12

Answer 12

now use this theorem:
if a quadrilateral has perpendicular diagonals, d1 and d2, then area=(d1 x d2)/2

Area = ( 12 x 8 ) / 2 = 48

Answer 13

so the answer is 48

Answer 14

please check and tell me if that is correct

Answer 15

is that the actual image or illustration for the problem? @perl

Answer 16

it is an example

Answer 17

where did you get the d1x d2/2 ? master @perl ? :))