One diagonal of a cyclic quadrilateral coincides with a diameter of a circle whose area is 36 pi cm^2. If the other diagonal which measures 8 cm meets the first diagonal at the right angles,find the area of the quadrilateral. Please help me :(

Question

perl · Answer

|dw:1414502740258:dw|

anonymous · Answer

what's next how can i find its area? :( please help me

anonymous · Answer

master @perl  what's next? :)

anonymous · Answer

@perl

perl · Answer

you to MIT ?

anonymous · Answer

mapua :)

perl · Answer

whats mapua?

anonymous · Answer

i mean can you guve me the solution for the problem @@perl ? :( =))

perl · Answer

sure, one sec

perl · Answer

If a quadrilateral has perpendicular diagonals, d1 and d2, then area=(d1 x d2)/2

anonymous · Answer

thank youu in advance!!! you are an angel! haha =)))

perl · Answer

Pi * r^2 = 36*Pi
r^2 = 36 
r = 6
now 
diameter = 2*r 
so 
diameter = 2*6 = 12

perl · Answer

now use this theorem:
if a quadrilateral has perpendicular diagonals, d1 and d2, then area=(d1 x d2)/2

Area = ( 12 x 8 ) / 2 = 48

perl · Answer

so the answer is 48

perl · Answer

please check and tell me if that is correct

anonymous · Answer

is that the actual image or illustration for the problem? @perl

perl · Answer

it is an example

anonymous · Answer

where did you get the d1x d2/2 ? master @perl ? :))