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Mathematics 16 Online
OpenStudy (precal):

How can the second derivative help me find the relative maximum and relative minimum of a function?

OpenStudy (anonymous):

Please come i need help http://openstudy.com/study#/updates/54502634e4b0c26d0cb2a905 PLease Explain and HElp

OpenStudy (precal):

I know the 2nd derivative will help me identify the point of inflection.

Miracrown (miracrown):

so there's this test called the second derivative test basically if you know an x value makes f' (x) = 0, then it is what we call a critical point it could be a minimum or a maximum, or neither. The second derivative test tells us which is the case. So, here's how it works...

Miracrown (miracrown):

you plug the x value into the 2nd derivative if you get a negative answer, that value of x is a maximum of the function if you get a positive answer, that x value is a minimum if you get 0, the test gives you no information

OpenStudy (precal):

but don't I need to use the first derivative to determine the location of the max or min

Miracrown (miracrown):

yes, the x values that could be min/max you get from the first derivative

Miracrown (miracrown):

then the 2nd derivative can tell you what type of special point those x values you get from the 1st derivative are

OpenStudy (precal):

ok now I see

OpenStudy (precal):

Thanks

Miracrown (miracrown):

2nd derivative can also tell you about concavity and inflection points as you mentioned at the beginning

Miracrown (miracrown):

and yw :)

OpenStudy (precal):

Don't I have to also, make sure that f"(x)=0 as well

Miracrown (miracrown):

only when you're finding inflection points

Miracrown (miracrown):

inflection points occur where the 2nd derivative changes sign where the graph goes from concave up to concave down or vice versa

Miracrown (miracrown):

but for finding whether a point is min/max, you just see what the value of the 2nd derivative is when you plug that x in

OpenStudy (precal):

thanks

Miracrown (miracrown):

yw

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