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Mathematics 8 Online
OpenStudy (anonymous):

Plutonium-240 decays according to the function where Q represents the quantity remaining after t years and k is the decay constant, 0.00011... How long will it take 36 grams of plutonium-240 to decay to 12 grams? A. 1.44 years B. 18,900 years C. 9,990 years D. 2,100 years

OpenStudy (anonymous):

according to the function ... let me guess, \[A(t)=A_0e^{-kt}\]

OpenStudy (anonymous):

well yes but the varible is actually Q but that dosent really matter, i just cant get the answer i dont know how to do it

OpenStudy (anonymous):

first replace \(k \) by \(-0.00011\) and \(Q_0\) by \(36\) to get \[\large Q(t)=36e^{-0.00011t}\]

OpenStudy (anonymous):

set that sucker equal to \(12\) and solve \[\large Q(t)=36e^{-0.00011t}=12\] in only three steps

OpenStudy (anonymous):

1) divide by 36 2) rewrite in logarithmic form 3) divide by \(-0.00011\)

OpenStudy (anonymous):

let me know if that is clear

OpenStudy (anonymous):

thanks for your help i got 9987.38 is that correct? would the answer be C?

OpenStudy (anonymous):

i have no idea, i didn't do it, but i would be happy to check the answer

OpenStudy (anonymous):

please do i want to see if ive done it correctly

OpenStudy (anonymous):

that is what i get too in any case the answer is almost always C, so you could have done this without doing any work at all

OpenStudy (anonymous):

haha thanks

OpenStudy (anonymous):

yw

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