Plutonium-240 decays according to the function where Q represents the quantity remaining after t years and k is the decay constant, 0.00011... How long will it take 36 grams of plutonium-240 to decay to 12 grams? A. 1.44 years B. 18,900 years C. 9,990 years D. 2,100 years
according to the function ... let me guess, \[A(t)=A_0e^{-kt}\]
well yes but the varible is actually Q but that dosent really matter, i just cant get the answer i dont know how to do it
first replace \(k \) by \(-0.00011\) and \(Q_0\) by \(36\) to get \[\large Q(t)=36e^{-0.00011t}\]
set that sucker equal to \(12\) and solve \[\large Q(t)=36e^{-0.00011t}=12\] in only three steps
1) divide by 36 2) rewrite in logarithmic form 3) divide by \(-0.00011\)
let me know if that is clear
thanks for your help i got 9987.38 is that correct? would the answer be C?
i have no idea, i didn't do it, but i would be happy to check the answer
please do i want to see if ive done it correctly
that is what i get too in any case the answer is almost always C, so you could have done this without doing any work at all
haha thanks
yw
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