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Physics 15 Online
OpenStudy (anonymous):

rocket propulsion: in deriving the equation for thrust, is the relative velocity of exhaust gasses and rocket: 1) -ver=-v-(v+dv) OR 2) -ver=v-(v+dv), while assuming the exhaust velocity is lower than the speed of the rocket. 2) makes more sense to me but for some odd reason, the textbook goes with 1)

OpenStudy (mendicant_bias):

Just mentioning this: I brought up Newton's Universal Law of Gravitation in the other question, but F = gM/^2 was what we were looking for. I'll be here in a sec.

OpenStudy (anonymous):

but i though f was Gmm/r^2

OpenStudy (mendicant_bias):

Yup, totally right, it is, just referring to the special case where only one force is acting on a constant mass, and the force is gravity. Just confusion, my bad. \[F_g = mg = \frac {GmM}{R^{2}} = \frac {gM}{R^{2}}\]Alright, now this.

OpenStudy (mendicant_bias):

Lol, I'm sleepy, the above was written wrong..but from the other post, you know what I mean.

OpenStudy (mendicant_bias):

Yeah, I know next to nothing about rocket propulsion, I can't help. I think I'm going to go fall on a pillow now..

OpenStudy (anonymous):

lol. thx anyway. good night. got uni tomorrow and its 12:30 here lol

OpenStudy (mendicant_bias):

Same thing, except none of my Physics classes have me needing to know rocket propulsion, so I can call myself lucky, haha

OpenStudy (anonymous):

are u in engineering too?

OpenStudy (mendicant_bias):

I'm a Physics major-which is why it's all the more terrible I know nothing about this. I'm just now taking E&M along with Ordinary Diff Eq.

OpenStudy (mendicant_bias):

In Physics I (Classical Mechanics) we never really needed to deal with stuff like that.

OpenStudy (anonymous):

nice!

OpenStudy (anonymous):

downward direction has been taken as negative. Hence the -v. Note you have to find relative velocity (direction is important)

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