Question

What are the x-intercept(s) of the graph of y + 6 = x2 − x?

(−2, 0) and (3, 0)

(−2, 0) and (−3, 0)

(2, 0) and (−3, 0)

(2, 0) and (3, 0)

I have an idea of how to solve this, I think it would be the x = -b/2(a) formula then to plug in, but I am at a complete loss.

Answer 1

no subtract 6 both sides

y = x2 - x - 6
factor the polynomial and then set y to zero

Answer 2

So i'm subtracting six from itself and x?

Answer 3

like this
y + 6 -6= x2 - x -6

Answer 4

For finding \(x\)-intercept, always put \(y=0\), the value of \(x\) you get is your \(x\)-intercept.. :)

Answer 5

Set \(y=0\) and find \(x\)..

Answer 6

Can you show me how to do that?

Answer 7

Sure :
\(y + 6 = x^2 - x\)

Set \(y = 0\) : \(0 + 6 = x^2 - x\)

Answer 8

\[x^2 - x = 6 \implies \color{green}{x^2 - x - 6 = 0}\]

Answer 9

Can you solve this quadratic equation and find \(x\)??

Answer 10

Not really, I am writing every thing you say down, but I am stumped

Answer 11

Haven't read Quadratic Formula?

Answer 12

Okay, tell me where are you having doubt?

Answer 13

Just, how to set this one up, I just feel so overwhelmed by it for some reason