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Solve the absolute value equations below:
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\[|x + 6|= 3\] A) x = 3 B) x = 3, -3 C) x = -3, -9 D) x = 6, -6
This breaks into two equations: \(x + 6 = 3\) and \(x - 6 = 3\) ----------------- \(x+ 6 = 3\) Subtract 6 to both sides: \(x = -3\) ----------------- \(x - 6 = 3\) Add 6 to both sides: What's 6 + 3? @pigglet
9
Yep, so the solutions are -3, and 9.
it would be -3,-9. there is no -3,9
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The second equation is -x-6 not x-6 I believe.
As it is the negative form of (x+6)
Oh..that's right, my bad..I made the second equation wrong. So it should be (-3, -9). 'Cause you have to multiply -1 to both sides which gives you -9..
Thanks @alrightatmaths
So its C
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That's ok, no worries
Yes. @pigglet
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