If a sample of aluminum carbonate contains 1.75 grams of aluminum [Al] atoms, calculate the mass (in grams) it contains of oxygen [O] atoms.

Question

lena772 · Answer

@SolomonZelman @e.mccormick @mathstudent55

anonymous · Answer

1.75 g aluminum carbonate(Al2O3) @ (53.96 g for 2 moles of Al) / (101.96 g/mol of Al2O3) = 0.926 g Al, so 0.93 grams of Al are in 1.75 g of Al2O3 
now just subtract. 
1.75 - 0.93 g Al = 0.82 grams of oxygen.. I think.

lena772 · Answer

Thanks for copying and pasting the wrong answer from Yahoo answers,

anonymous · Answer

I mean I was just trying to help. That's what the "I think" was for. Sorry.

cuanchi · Answer

Al2(CO3)3=233.99 g mol−1
Al= 23.06%
O=61.54%

1.75g Al x 61.54 g Oxygen/ 23.06 g Al = 4.67g oxygen