Question

Can I please get help with this two part question.
Part A: If (7^2)^x=1, what is the value of x?
Part B: If (7^0)^x=1, what are the possible values for x?

Answer 1

If you have \(\large\color{blue}{ a^x=1 }\) and \(\large\color{blue}{ a≠1 }\) then \(\large\color{blue}{ x=0 }\).

Answer 2

So then part a would be 0?

Answer 3

For the second one, when you have 1^x=1, x can be either ±1 or 0

Answer 4

i cant see what u wrote it comes out as ??????

Answer 5

yes part a is zero.

Answer 6

refresh (?)

Answer 7

you there?

Answer 8

i keep on loosing connection

Answer 9

happens

Answer 10

solomonZelman do u mind helping me with a few more?

Answer 11

sure, but do you know everything till now?

Answer 12

yes

Answer 13

alright

Answer 14

(2^8 * 5^-5 * 19^0) * (5^-2)^4 * 2^28
----
( 2^3)

Answer 15

should i draw it to make it easier to see?

Answer 16

I see:)

Answer 17

5^-2 will equal to what with a positive exponent ?

Answer 18

1?

Answer 19

\(\huge\color{blue}{ a^{-b}= \frac{1}{a^b} }\)

For example. \(\huge\color{blue}{ 5^{-2}= \frac{1}{5^2}=\frac{1}{25} }\)

Answer 20

So can you tell em what will 5^-5 be?

Answer 21

don't simply just do the parts with positive exponents.

Answer 22

so would it be 1/25?

Answer 23

that is 5^-2.
just leave it as 5^2 for now.

Answer 24

I mean leave it as 1/5^2

Answer 25

and 5^-5 is ?

Answer 26

5*5*5*5*5?

Answer 27

well,
5^-5 = 1/(5^5)
right?

Answer 28

yes

Answer 29

So step 1:

\(\huge\color{blue}{ \frac{(2^8 \times 5^{-5} \times 19^0)(5^{-2})^{4}\times 2^{28}}{2^3} }\)

\(\huge\color{blue}{ \frac{(2^8 \times 5^{-5} \times 1)(5^{-2})^{4}\times 2^{28}}{2^3} }\)

\(\huge\color{blue}{ \frac{(2^8 \times 5^{-5})(5^{-2})^{4}\times 2^{28}}{2^3} }\)

good ?

Answer 30

yes can you give me two minutes to write that down? plz

Answer 31

sure

Answer 32

Step 2:

\(\huge\color{blue}{ \frac{(2^8 \times 5^{-5})(5^{-2})^{4}\times 2^{28}}{2^3} }\)

\(\huge\color{blue}{ \frac{(2^8 \times 5^{-5})(5^{-8})\times 2^{28}}{2^3} }\)

Answer 33

\(\huge\color{blue}{ \frac{2^8 \times 5^{-5} \times5^{-8}\times 2^{28}}{2^3} }\)

Answer 34

in step 1 did u miss a number?

Answer 35

I know that 19^0=1, right?

Answer 36

and multiplying times 1, is just like not multiplying by anything.

Answer 37

the first 1 in step 1?? theres no 2 to the 3rd power

Answer 38

nvm

Answer 39

can u give me two minutes plz to write it all down

Answer 40

I can type it and you can copy it all.... or whatever works for you.

Answer 41

i cant copy it, its not letitng me do that

Answer 42

you can't copy these Latex symbols-:(

Answer 43

you can write it on a paper, or take type to type it, it won't go anywhere.

Answer 44

take time to type it *

Answer 45

i typed it all

Answer 46

so continuing from where I left off.

The last thing I had is.


\(\huge\color{blue}{ \frac{2^8 \times 5^{-5} \times5^{-8}\times 2^{28}}{2^3} }\)

Answer 47

i got that down

Answer 48

So,

\(\huge\color{blue}{ \frac{2^8\times\frac{1}{5^5}\times\frac{1}{5^8}\times 2^{28}}{2^3} }\)

Answer 49

\(\huge\color{blue}{ \frac{2^8\times 2^{28}}{2^3\times 5^5 \times 5^8} }\)

Answer 50

\(\huge\color{blue}{ \frac{2^8\times 2^{28}}{2^3\times 5^{13}} }\)

Answer 51

\(\huge\color{blue}{ \frac{2^3\times2^5\times 2^{28}}{2^3\times 5^{13}} }\)

Answer 52

\(\huge\color{blue}{ \frac{2^5\times 2^{28}}{5^{13}} }\)

Answer 53

\(\huge\color{blue}{ \frac{2^{33}}{5^{13}} }\)

Answer 54

http://www.wolframalpha.com/input/?i=2%5E33%2F5%5E13

Answer 55

you can write an answer in any form,. or just leave the last blue that I wrote. Depends on what your teacher exactly wants.

Answer 56

ok im typing it give me two more minutes plz

Answer 57

i got it thank u 1 more?

Answer 58

The mass of the Eiffel Tower is about 9.16 ⋅ 10^6 kilograms. The mass of the Golden Gate Bridge is 8.05 ⋅ 10^8 kilograms. Approximately how many more kilograms is the mass of the Golden Gate Bridge than the mass of the Eiffel Tower? Show your work and write your answer in scientific notation.

Answer 59

I am tired.
Please close this question and open new one.

You have an unlimited number of questions, but you have to ask 1 question per thread.

Answer 60

tnx for your cooperation.

Answer 61

ok so all i ogtta do is ask it on a new thread?

Answer 62

thank u so so much for ur help