Question

f(x)=2x-2/x^2+x-2
What values of x is f(x) discontinuous?

Answer 1

\[f(x)=\frac{ 2x-2 }{ x^2+x-2 }\]

Answer 2

I've done the work and ended up with \[\frac{ 2 }{ x+2 }\] but I do not know about the discontinuities.

Answer 3

a=f(x) =(2x-2)/(x^2+x-2)
=(2x-2)/(x-1)(x+2)
=2/(x+2)
f(x) is undefined at x= -2 & x=1
b=lim 2/(x+2) = -infinity
x-->-2
c)x=-2
lim 2/(x+2) = 0
x->infinity
d)2/(x+2) = a/(b + x)

Answer 4

....what..

Answer 5

f(x) is undefined at x= -2 & x=1

Answer 6

That's not what the problem is asking for. It's asking me to define the discontinuities. I'm aware that x=-2 and x=1 are non-removable discontinuities but I don't know if I'm missing anything else.

Answer 7

. . . Seems like you got it.

Answer 8

Thanks love. :)

Answer 9

Mhm. ^^