Mathematics
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OpenStudy (anonymous):
The area of a rectangular piece of land is 280 square meters. If the length of the land was 5 meters less and the width was 1 meter more, the shape of the land would be a square.
Part A: Write an equation to find the width (x) of the land. Show the steps of your work. (5 points)
Part B: What is the width of the land in meters? Show the steps of your work. (5 points)
12 years ago
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OpenStudy (anonymous):
@ganeshie8
12 years ago
OpenStudy (anonymous):
Help please
12 years ago
OpenStudy (anonymous):
@ganeshie8
12 years ago
OpenStudy (anonymous):
No
12 years ago
OpenStudy (anonymous):
can you post the links over here
12 years ago
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OpenStudy (anonymous):
I already have.
12 years ago
OpenStudy (anonymous):
but its just one, can you post a few
12 years ago
OpenStudy (anonymous):
@ganeshie8 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
12 years ago
OpenStudy (anonymous):
@ganeshie8 may you please help me, I've been stuck on this for so long
12 years ago
OpenStudy (anonymous):
@ganeshie8 I will give you a medal
12 years ago
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ganeshie8 (ganeshie8):
say the width of original land is \(x\) and length is \(y\)
12 years ago
OpenStudy (anonymous):
ok
12 years ago
ganeshie8 (ganeshie8):
`If the length of the land was 5 meters less and the width was 1 meter more, the shape of the land would be a square.`
12 years ago
ganeshie8 (ganeshie8):
what do you know about sides of a square ?
12 years ago
OpenStudy (anonymous):
^2
12 years ago
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OpenStudy (anonymous):
since there are two sides
12 years ago
ganeshie8 (ganeshie8):
we use the fact that the sides of a square are equal
12 years ago
OpenStudy (anonymous):
ok
12 years ago
ganeshie8 (ganeshie8):
\(\large y-5 = x+1 \tag{1} \)
12 years ago
OpenStudy (anonymous):
That's the equation?
12 years ago
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ganeshie8 (ganeshie8):
since the area of original land is 280 :
\[\large xy = 280\tag{2}\]
12 years ago
OpenStudy (anonymous):
ok I am understanding so far
12 years ago
ganeshie8 (ganeshie8):
isolate y from first equation and substitute it in 2nd equation
12 years ago
ganeshie8 (ganeshie8):
from first equation you get : \(\large y = x + 6\) right ?
12 years ago
OpenStudy (anonymous):
Yes
12 years ago
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ganeshie8 (ganeshie8):
plug that in second equation, you will get a quadratic :
\[\large xy = 280\\x(x+6) = 280\\x^2+6x-280=0\]
12 years ago
ganeshie8 (ganeshie8):
thats the final equation for part A
12 years ago
ganeshie8 (ganeshie8):
solve that equation for part B
12 years ago
OpenStudy (anonymous):
SO x^2+6x-280?
12 years ago
ganeshie8 (ganeshie8):
x^2+6x-280 = 0
12 years ago
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ganeshie8 (ganeshie8):
an equation must have an "=" symbol somewhere
12 years ago
OpenStudy (anonymous):
WHat do I solve for
12 years ago
ganeshie8 (ganeshie8):
x
12 years ago
OpenStudy (anonymous):
I got 14 and -20
12 years ago
ganeshie8 (ganeshie8):
can the width be negative ?
12 years ago
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OpenStudy (anonymous):
no
12 years ago
ganeshie8 (ganeshie8):
so throw away -20
12 years ago
OpenStudy (anonymous):
and 14 is correct?
12 years ago
ganeshie8 (ganeshie8):
width = x = 14
12 years ago
OpenStudy (anonymous):
Are you sure?
12 years ago
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ganeshie8 (ganeshie8):
if you're sure, im also sure
12 years ago