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Pre-Algebra
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Solve the radical equation...
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\[\sqrt{x=7}-\sqrt{x-2}=1\] \[\sqrt{x+7}=1+\sqrt{x-2}\] \[(\sqrt{x+7})^{2}=(1+\sqrt{x-2})^{2}\]
I think it's x=18
Was I doing it right?
on the last step that I did, is it correct?
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yes
\[\sqrt{x+7}=1+x-2\] This is my last step but I failed.
ok
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