Question

solve the equation on the interval 0 11 years ago

Answer 1

you know a number whose cosine is \(\frac{\sqrt{3}}{2}\) ?

Answer 2

should look kind of familiar

Answer 3

\[\pi/6 , 11\pi/6\]

Answer 4

ok so if \(2\theta=\frac{\pi}{6}\) then that makes \(\theta =\frac{\pi}{12}\)
that is one of the answers, there are more

Answer 5

so then \[11\pi/12\] would be the second?

Answer 6

that would be the second one, but there may be more

Answer 7

because if you go around the unit circle again, you get to
\[\frac{13\pi}{6}\] which is not in the interval \([0.2\pi]\) but half of it is

Answer 8

would tou also do cos= \[-\sqrt{3}/2\]

Answer 9

no, it doesn't say anything about that

Answer 10

but if
\[2\theta =\frac{13\pi}{6}\] then
\[\theta=\frac{13\pi}{12}\]which is in your interval

Answer 11

then 23pi/12 can also be an option cause its in that interval