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The top of a ladder slides down a vertical wall at a rate of 0.125 m/s. At the moment when the bottom of the ladder is 5 m from the wall, it slides away from the wall at a rate of 0.3 m/s. How long is the ladder?
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Ok so I know that I have to set it up as 2x(dx/dt)+2y(dy/dt)=2z(dz/dt)
But how do I find z with just the information given?
correct so far
you can use pyth. theorem x^2 + y^2 = z^2
But I only have length of one side
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z is constant, so dz/dt = 0
z is the length of the ladder, that doesnt change
so 2x(dx/dt)+2y(dy/dt)=2z(dz/dt) becomes 2x(dx/dt)+2y(dy/dt)=2z*0 2x(dx/dt)+2y(dy/dt)=0
oh that makes a lot of sense thanks!
and divide out 2
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