Evaluate the limit
Two options. Either multiply top and bottom by the conjugate of the bottom, or take advantage of difference of squares: \[a-b = (\sqrt{a} - \sqrt{b})(\sqrt{a} + \sqrt{b})\]
ok i think id rather take the conjugate
Either works :) The difference of squares option isn't as obvious when you're not used to it with things that aren't actually like \(x^{2}-4\). But it can be done with the anything that is a-b form.
the conjugate is \[1+\sqrt{1}\] right?
Top and bottom by \(1+\sqrt{b}\)
ok once we do that do i multiply them out?
Multiply out the bottom one. Multiplying out the top one makes it hard to see what happens.
ok so how does the bottom look like?
1-b?
then that cancels out with the top right ?
\[\frac{ (1-b)(1+\sqrt{b}) }{ (1-\sqrt{b})(1+\sqrt{b}) } = \frac{ (1-b)(1+\sqrt{b}) }{ 1+\sqrt{b}-\sqrt{b}-b } = \frac{ (1-b)(1+\sqrt{b}) }{ 1-b }\]
Yes, then it would cancel :)
then 1+\[\sqrt{b}\]
would be left over right?
Yep. And then you can plug in your limit.
so the answer would be 2
Yes :3
ah yes thank you
You're welcome :)
Join our real-time social learning platform and learn together with your friends!