Question

Solve for x: −3x + 3 < 6

x > −1

x < −1

x < −3

x > −3

Answer 1

-3x + 3 < 6

Subtract 3 to both sides:

-3x < 3

Divide -3 to both sides, what's 3 / -3? @Kidthatbro8

Answer 2

-1 ?

Answer 3

Yep, so we have x > -1.

Don't forget to switch the sign when dividing by a negative number.

Answer 4

oh, thanks ! c:

Answer 5

@Hero so is the answer x> - 1 or x <-1??

Answer 6

I can walk you through how to solve it.

Answer 7

could you? That would be great! @Hero

Answer 8

First, write down the original problem:
−3x + 3 < 6

Afterwards, subtract 3 from both sides.

Answer 9

ok so -3x <3?

Answer 10

Add 3x to both sides.

Answer 11

how do I do that?

Answer 12

x<6?

Answer 13

By actually adding 3x to both sides.

Answer 14

-3x + 3x < 3 + 3x

Answer 15

x<6x?

Answer 16

What is -3x + 3x ?

Answer 17

0x?

Answer 18

Yes, and what is zero times x?

Answer 19

0?

Answer 20

Exactly.

Answer 21

So you should have 0 < 3 + 3x

Answer 22

The next thing to do is subtract 3 from both sides again.

Answer 23

-3 < 0x?

Answer 24

No, you have confused yourself somehow. If you subtract 3 from both sides, nothing happens to the 3x

Answer 25

You had 0 < 3 + 3x

After subtracting 3 from both sides, you should have

-3 < 3x

Answer 26

ohhh so -3<3x?

Answer 27

Yes, now divide both sides by 3.

Answer 28

-1<1x

Answer 29

Which simplifies to just -1 < x

Answer 30

ohhh

Answer 31

So what do you think is the correct answer?

Answer 32

x>-1

Answer 33

Correct.

Answer 34

Thank you so muh!!!!

Answer 35

Basically, the technique that I use avoids having to divide by negative.

Answer 36

Which, in my opinion, eliminates a lot of confusion.

Answer 37

It may seem like a lot at first, but once you get used to doing it that way, it becomes really easy.

Answer 38

Really, all you're doing is isolating x just like you would a regular equation, except you don't have to worry about "flipping signs"

Answer 39

Do you have any other problems you'd like to go over @haloqueenB258

Answer 40

no, thanks though! @Hero