Question

what is the 6th term of the geometric sequence where a1= -4096 and a4= 64?

answers:
-1
4
1
-4

Answer 1

an= ar^(n-1)
a1 = -4096
a4 = 64
64 = -4096* r^3

Answer 2

well you need to find the common ratio... r

a term in a geometric sequence is


\[a_{n} = a_{1} \times r^{n - 1}\]

so using the information provided you can find r

\[64 = -4096 \times r^{4 -1}\]

so

\[\frac{64}{-4096} = r^3\]

solve for r,

then use the formula above to find the 6th term, n = 6, a = -4096 r =

Answer 3

it is