Anyone answer these for me? MEDAL!!! http://gyazo.com/39b4f403c137515b8efece77341694f5

Question

anonymous · Answer

no

kidthatbro8 · Answer

to be honest, no, because 1. this isn't the mathematics board, and 2. we aren't allowed to give out answers, just help you to figure them out.

anonymous · Answer

@wio

anonymous · Answer

only need help with 2 and 3 buddy @wio

anonymous · Answer

Axis of symmetry is just a line which divides the parabola into two symmetrical halves.

anonymous · Answer

how do i make the equation into general form?

anonymous · Answer

@aum

anonymous · Answer

Do you know how to get it into vertex form?

anonymous · Answer

no sir

aum · Answer

I suppose the general form could be: 2x^2 + 12x - 10 = 0 
This is a vertical parabola that opens upward. 
The axis of symmetry will be a vertical line passing through the vertex. 
The x-coordinate of the vertex is given by -b/(2a) = -(12)/(2*2) = -3. 
x = -3 is the axis of symmetry.

aum · Answer

#3.  Any general point (x,y) on the parabola is equidistant from the focus and directrix.  Focus (3, 6).  Directrix y = 4.  Therefore, 
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
(x-3)^2 = (y-4)^2 - (y-6)^2 = (y-4+y-6)(y-4-y+6) = (2y-10)(2) = 4(y-5)
y = 1/4 * (x-3)^2 + 5  in vertex form.
If necessary you can put it in standard form.

anonymous · Answer

Thanks @aum really appreciate the help

arabpride · Answer

cx http://openstudy.com/study#/groups/Mathematics