Determine the domain of the function. f as a function of x is equal to the square root of two minus x.
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OpenStudy (cwrw238):
is it
f(x) = sqrt(2 - x) ?
OpenStudy (anonymous):
yes
OpenStudy (cwrw238):
the domain is the set of possible values of x
Hint: as you have a square root here (2-x) cannot be negative)
OpenStudy (cwrw238):
- so for example x cannot be equal to 3 as 2-x will = -1 and there are no real square roots of -1
OpenStudy (anonymous):
So would it be x is less than or equal to 2?
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OpenStudy (cwrw238):
yes
OpenStudy (anonymous):
thanks!
OpenStudy (cwrw238):
yw
OpenStudy (cwrw238):
in interval form you would write this as (-infinity, 2]
OpenStudy (anonymous):
what about this one?? \[f(x)=\sqrt{x+3}\div(x+8)(x-2)\]
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OpenStudy (cwrw238):
domain of the numerator can be found in similar way as with the first function.
as for the denominator x=-8 and x = 2 cannot be part of the domain because they make the denominator zero.