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OpenStudy (anonymous):
@iambatman @Hero an arithmetic sequence consists of 21 terms. the sum of three terms in the middle is 129, and the last three have a sum of 237. find the series.
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OpenStudy (tkhunny):
Arithmetic Sequence: 1st term: a 2nd Term: a+r 3rd Term: a+2r 4th Term: a+3r etc. "an arithmetic sequence consists of 21 terms." a + (a+r) + (a+2r) + ... + (a + 20r) "the sum of three terms in the middle is 129" Terms 9, 10, and 11 (a+8r) + (a + 9r) + (a+10r) = 129 "last three have a sum of 237" Terms 19, 20, and 21 (a+18r) + (a + 19r) + (a+20r) = 237 That is tons of information. Go!
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