Question

limit x approaches negative infinity xe^-x

Answer 1

Nice copy and paste from Yahoo Answer...

Answer 2

@Markiplier, you answer have something missing or you misunderstood the question. It's x*e^(-x)

Answer 3

I don't really know the appropriate approach, but if you do direct substitution, you will get \(-\infty\cdot\infty\)

One approaches to infinity and other approaches to negative infinity;

Multiplying them and you pretty much have a negative infinity.

So \(\displaystyle \lim_{x\to-\infty}xe^{-x}=\boxed{-\infty}\)

Answer 4

Thanks so much, yeah I think that what you did is correct. Thanks again

Answer 5

No problem