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Mathematics 11 Online
OpenStudy (anonymous):

http://gyazo.com/29f78e24c5b6ecaba499910a573e7630 For the y-intercept, could i just plug in 0 into the x and just do it like that?

OpenStudy (anonymous):

For example, 13 would be -14? @zepdrix @ganeshie8 @mathmale

OpenStudy (mathmale):

Can't see your posted problem (yet). In general, yes: you do let x=0 and then calculate y. But that's not enough; you must present the y-intercept as a POINT: (x,y). Here, obviously, x=0. What is y?

OpenStudy (anonymous):

You can't see it? It's the Gyazo link.

OpenStudy (mathmale):

Yes, it's visible now, but downloading to my computer was slow.

OpenStudy (anonymous):

Oh ok

OpenStudy (anonymous):

So would first one be -14 ?

OpenStudy (mathmale):

You're on the right track. But what does that '-14' represent?

OpenStudy (anonymous):

y

OpenStudy (anonymous):

so (0,-14) ?

OpenStudy (mathmale):

OK, so now you realize that x=0 and y=-14. Take that info and write the POINT that represents the y-intercept.

OpenStudy (mathmale):

Yes. Very good.

OpenStudy (mathmale):

Now find the y-intercept of #14.

OpenStudy (anonymous):

(0,3/4) ?

OpenStudy (mathmale):

Beautiful.

OpenStudy (anonymous):

How do i approach 15, 16 and 17?

OpenStudy (mathmale):

Please start out by sharing YOUR ideas about that for #15.

OpenStudy (mathmale):

Hint: two parallel lines have ______________ slopes.

OpenStudy (anonymous):

parallel ?

OpenStudy (mathmale):

Hint #2: The slopes of perpendicular lines are __________________________ .

OpenStudy (mathmale):

The lines are parallel (given), but the slopes are not parallel. Think of another descriptor for the slopes of parallel lines.

OpenStudy (anonymous):

hmmm. idk

OpenStudy (mathmale):

equal. Type the whole thing out, including 'equal.'

OpenStudy (anonymous):

So CD would be -3 also?

OpenStudy (mathmale):

Of course I know what y ou're saying, but what you're saying would be a lot clearer if you'd type, "the slope of line CD is -3 also."

OpenStudy (mathmale):

-3 is the value of a slope, whereas CD represents a line connecting points C and D.

OpenStudy (anonymous):

So the slope of CD would be positive 3?

OpenStudy (mathmale):

Which problem are you discussing, 14 or 15?

OpenStudy (anonymous):

15

OpenStudy (mathmale):

Hold

OpenStudy (mathmale):

In number 15, you are told that lines AB and CD are PARALLEL to one another. What do y ou know about the slopes of PARALLEL lines?

OpenStudy (anonymous):

they are the same?

OpenStudy (anonymous):

No, they are opposite

OpenStudy (mathmale):

Actually, the slopes of two parallel lines ARE the same.

OpenStudy (mathmale):

Ditch that "No, they are opposite" statement. You may have meant: The slopes of perpendicular lines are 'negative reciprocals' of one another (not 'opposites').

OpenStudy (anonymous):

oh, so the slope of line CD would be positive 3 right?

OpenStudy (mathmale):

Answer #15 again: "The slope of line CD is "

OpenStudy (mathmale):

why do you feel it's POSITIVE instead of NEG?

OpenStudy (anonymous):

Oh so its negative?

OpenStudy (anonymous):

The slope of line CD is -3

OpenStudy (mathmale):

Repeat: the slopes of parallel lines are EQUAL. The slopes of perpendicular lines are 'negative reciprocals' of each other.

OpenStudy (mathmale):

Right, the slope of line CD is -3, becuase line CD is parallel to line AB, which has a slope of -3. Again, right.

OpenStudy (mathmale):

Regarding Problem #16: Please go back and re-read what I wrote above, "The slopes of perpendicular lines are ....

OpenStudy (anonymous):

And then 16 would be -5/2 then.

OpenStudy (mathmale):

Yes. You took slope 2/5 of the first line and then found the 'negative reciprocal' of it, obtaining -5/2. Very good. Type out the answer to #16 using the proper vocabulary.

OpenStudy (anonymous):

And then 17 is -1/7

OpenStudy (anonymous):

Hey thank you soooo much @mathmale . You've saved my life lol

OpenStudy (mathmale):

What is the slope of the line connecting points A and B?

OpenStudy (mathmale):

delighted to hear that I've been of help. Very happy to spend this time with you.

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