Find equation of slope and graph: m=2 (3,5) would the answer be 5=2(3)+b?
point slope form: \[(y-y_1) = m(x-x_1)\]
m is the slope. (x1,y1) is the coordinates. just plug in the given values
So it would be (y-5)=2(x-3?
So y-5=2x-6
simplify further by combining the constant terms
y=2x-1?? (:
yep. if you wanted to have the equation in slope-intercept form, then that's already the answer but if you wanted to have it in standard form then it will be in the form : Ax+By+C=0
Okay, may I go over another one with you real quick? (:
sure
Wait first I have to check the ordered pair for the last problem.. How do I check ordered pairs?
Oh never mind!
say for the question above, all you have to do is plug in the value of x to the equation. check the value of y if it corresponds to the y-coordinate of the given point
Got it (: So the other one I was going to go over with you is m=2 (-4,-6)
Soooo.. (y+6)=2(x+4) ???
Then y+6=2x+8
yep.
go on
combine the constant terms
So it would be.. y=2x+10!
recheck the value for constant
Oh wow... Lol oops. y=2x-2
check the sign of the constant xD
+ oops haha
so the equation would be y = 2x +2
Yes got it!(: Now I'm going to try one on my own and see if I'm right one second (:
Okay so for m=2/5 (3,1) I got the equation y=0.4x-.2
@shinalcantara What is the standard equation of line??
According to me it is : \(ax + by = c\)
Ax+By+C=0
No, that is Shinalcantara Equation of line.. :P
hi prrreeeeeeetttttt!!!!! =) :)
Hi Sheeeenaaaaaaaaaaaaa... :P
:) @waterineyes what are you gonna say to msbambigirl? would you want that equation to be in decimal? O_O
Which equation??
I figured it out haha(: I need help with m being undefined and coordinates being (-2,4)!
y=0.4x-.2 that one up up up
I only said that \(ax + by + c = 0\), you said it is Standard Form but actually it is not..
@msbambygirl "Okay so for m=2/5 (3,1) I got the equation y=0.4x-.2" can you express that not in decimal?
No o:
O_O what's the standard form of the line then? @waterineyes
It is : \(ax + by = c\) :) Constant term on Right Side and coefficient of \(x\) should be positive.. :)
I need help on a different one ;-;
\[(y-y_1) = m(x-x_1)\] \[(y-1) = \frac{ 2 }{ 5 }(x-3)\] \[3(y-1)=2(x-3)\] 3y - 3 = 2x - 6 3y - 2x = -6 + 3 3y - 2x = -3 -----in standard form would this be correct @waterineyes O_O
@msbambygirl for m to be undefined, the change of x must be zero
So it would be (y-4)=0(x+2)??
No that is not correct.. :P
I said, the coefficient of \(x\) should be positive, and not of \(y\).. :P
\(2x - 3y = 3\), This looks fine.. :)
O_O
O--O
@msbambygirl for the line to have an undefined slope, it should be a vertical line in that case, the value for your x-coordinate will be constant while that of y is infinity
So how would I even write that?
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For slope of line as Undefined, y can take any value.. But, the value of \(x\) will remain same for every \(y\)..
So, the equation of line with having slope undefined is written as : \(x = k\)
\(k\) is the \(x\) coordinate from where the line touches x-axis.
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