Question

Joshua wrote the following proof to show that the diagonals of rectangle ABCD are congruent:

Joshua's proof:
Statement 1: In right triangle ADC, the sum of the squares of sides AD and DC is equal to the square of hypotenuse AC so that AD2 + DC2 = AC2 and in right triangle ABD, the sum of the square of sides AD and AB is equal to the square of hypotenuse DB so that AD2 + AB2 = DB2 (by Pythagorean Theorem)
Statement 2: AB = DC (by transitive property of equality)
Statement 3: AC2 = DB2 (from statements 1 and 2)
Statement 4: AC = DB (taking square root on both sides of AC2 = DB2)

Answer 1

Which statement in Joshua's proof has an error?

Answer 2

do you see what he did wrong?
Statement 2: AB = DC (by transitive property of equality)
Statement 3: AC2 = DB2 (from statements 1 and 2)

Answer 3

No. Because I suck. :c

Answer 4

I'll show you the picture that goes with it. holddd on.

Answer 5

http://gyazo.com/7d86d03500b812a17619c4f0da760f0d

Answer 6

It would be Statement 2 maybe? I'm not sure.

Answer 7

I lied. I have no idea what I'm doing.

Answer 8

LOLOL

Answer 9

I thought it was statement 2, but it appears I misread the question. try reposting it in math to get a better answer

Answer 10

Wow I thought I did post it in math tbh. Jfc. Whoops.

Answer 11

you failure

Answer 12

I mean, you'll get 'em next time

Answer 13

Oh thanks. You really know how to make someone smile.

Answer 14

And maybe close this question. :)