Question

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).

Answer 1

What should the slope of the new line be?

Answer 2

5x +1?

Answer 3

y=mx+b
where m is the slope. I just want the m value of the new line

Answer 4

5?

Answer 5

correct. now how do we find the equation of a line with slope 5 that passes through (4,5)?

Answer 6

i have no idea ? is there a formula

Answer 7

there's something called point slope form. it looks like this \(y – y_1 = m(x – x_1)\)
where x1 and y1 are the x and y coordinates of the point we want

Answer 8

god dammit
y-y1=m(x-x1)

Answer 9

haha ok so do i substitute y and x with (4, 5) ?

Answer 10

well x1 and y1*

Answer 11

but how would i solve that i dont have a y or x?

Answer 12

you don't have to solve it. you just simplify it and then get it into slope-intercept form (y=mx+b)

Answer 13

y- 5 = m (x -4)

Answer 14

correct. what is m?

Answer 15

i don't know :( how do i get m?

Answer 16

m is what we call the slope. if we want parallel lines, we want the same slope as the original line

Answer 17

5x + 1?

Answer 18

just 5. y=mx+b
here the 5 is attached to the x, so m=5

Answer 19

wait i dont understand my choices are
A) y = 5x − 15
B) y = 5x + 15
C) y = 1 over 5x + 21 over 5
D)

Answer 20

y- 5 = 5 (x -4) distribute the 5
y-5 = 5x-20

now simplify

Answer 21

y = 5x - 15

Answer 22

yep

Answer 23

thankyou !!

Answer 24

np np

Answer 25

Hi