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Help please will fan and give a medal. 2y^4 over 9x^5y divided y over 6x^2
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@ikram002p
4y^2 over 3x^3
\(\frac{2y^4}{9x^5y}/ \frac{y}{6x^2} \) first thing to do is change it to product instead of divide like this \(\frac{2y^4}{9x^5y}. \frac{6x^2}{y}\)
Just go here to help you with the steps http://www.cymath.com/answer.php?q=(2y%5E4)%2F(9x%5E5y)*(6x%5E2)%2F(y)
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:)
So is correct answer 4/3y^2x^3
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yes that the answer
nope its 4y^2/3x^3
4y^2 over 3x^3
Ok thank you both @ikram002p and @Ese_Muerte
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