Question

determine G''(4)

Answer 1

I'm looking for the fastest way to solve this.

Answer 2

\[G(4)=0\]

Answer 3

but that doesn't mean \(G''(4)=0\)
you have to actually that the derivative
in this case using the product rule and the chain rule

Answer 4

0_o nevermind the question was determine G'(4)

Answer 5

thanks though.

Answer 6

oh then that is much much easier!

Answer 7

think of it as
\[G(x)=xF(x)\] so the derivative is
\[G'(x)=F(x)+xF'(x)\] and
\[G'(4)=F(4)+4F'(4)\]

Answer 8

where \(F\) is the integral, so \(F(4)=0\)

Answer 9

yeah like that
you are way ahead of me
how did you get \(\arctan(\sqrt2 -1)\)

Answer 10

where?

Answer 11

it is \(\frac{\pi}{8}\) just wondering

Answer 12

oh nvm it is \(\arctan(1)\) doh ignore me

Answer 13

it is \[\arctan(\sqrt{4}-1)\]

Answer 14

haha ok

Answer 15

yeah you are right i am senile today